Derivar la siguiente funcion
f(x)=7x^2-x+e^2
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Sen (x-3)

Respuestas

Respuesta dada por: yexs
1
f(x)=  \frac{7x\²-x+e\²}{sen(x-3)}  \\  \\ f'(x)= \frac{(7x\²-x+e\²)'(sen(x-3)-(7x\²-x+e\²)(sen(x-3)'}{[sen(x-3)]\²}  \\  \\f'(x)=  \frac{(14x-1)(sen(x-3)-(7x\² -x+e\²)(cos(x-3)}{sen\²(x-3)} \\  \\ f'(x)=(14x-1)cosec(x-3)-(7x\²-x+e\²)tang(x-3)cosec(x-3)  \\  \\ \boxed{\boxed{f'(x)=cosec(x-3)[14x-1-(7x\²-x+e\²)tang(x-3)]}}\\  \\ .
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