Question

(q/q-3) - (6/q^2 -2q-3) = 1 resolver la ecuacion

Answer 1

(q/q-3) - (6/q² -2q-3) = 1
 
= (q/q-3) - [6/ (q-3)(q+1) ] = 1
[q(q+1) - 6(1)]/(q-3)(q+1)= 1
(q²+q-6) / (q-3)(g+1) = 1
(q +3)(q-2) = (q-3)(q+1) 
q²+q-6 = q²-2q-3
q²-q²+q+2q = -3+6    (pasamos la q a la izquierda y los numeros a la derecha)
3q=3
q= 3/3
q= 1

Comprobamos:

(1/1-3) - (6/1² -2(1)-3) = 1
(1/-2)-(6/1-5) = 1
(-1/2)-(6/-4) = 1
(-1/2)+3/2 = 1
(-1+3)/2 = 1
2/2 = 1
1 = 1