como se resuelven estas ecuaciones

2x+7=15
5x-1=-15
4x-3=21
-2=2x-8
4x-1=2x+9
5x+3-2x=x-17
4(x-3)=28
5(2x+1)=4(3x-1)
-5(x+1)=0
2(3x+5)=-3(4x-6)

Respuestas

Respuesta dada por: YanoMotOharU22
3
2x+7=15
2x = 8
x = 4

5x-1=-15
5x = -14
x = -14/5

4x-3=21
4x = 24
x = 6

-2=2x-8
-2+8 = 2x
6 = 2x
3 = x

4x-1=2x+9
2x = 10
x = 5

5x+3-2x=x-17
4x = -21
x = -21/4

4(x-3)=28
4x-12 = 28
4x = 40
x = 10

5(2x+1)=4(3x-1)
10x+5 = 12x -4
9 = 2x
9/2 = x

-5(x+1)=0
-5x-5 = 0
-5x = 5
x = 5/-5
x = -1

2(3x+5)=-3(4x-6)
6x+10 = -12x+18
22x = 8
x = 8/22
x = 4/11

Espero te haya servido... .

020494: gracias
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