Question

Si:
P(x,y)=7xy-5y^2
Q(x,y)=5y^2-2xy+x^2
R(x,y)=y^2-xy-6x^2
Calcula:
P(X,Y)+Q(X,Y)
Q(X,Y)-R(X,Y)

Answer 1

P(x,y)=7xy-5y^2
Q(x,y)=5y^2-2xy+x^2
R(x,y)=y^2-xy-6x^2

entonces nos pide:

P(x,y)+Q(X,Y) eso es igual a :

P(x,y)+Q(x,y) = 7xy - 5y^2 + 5y^2 - 2xy + x^2

►P(x,y)+Q(x,y) = 5xy + x^2

la otra queda:

Q(X,Y)-R(X,Y) = 5y^2 - 2xy + x^2 - (y^2 - xy - 6x^2)

Q(X,Y)-R(X,Y) = 5y^2 - 2xy + x^2 - y^2 + xy + 6x^2

►Q(X,Y)-R(X,Y) = 4y^2 - xy + 7x^2

SALUDOS!