Determina las raíces de las siguientes ecuaciones cuadráticas
1) x2 – 3x = 0
2) 6x2 + 42x = 0
3) x2 + ax = 0
4) x2 – 18x + 80 = 0
5) x2 – 4x – 96 = 0
6) x2 – 17x + 52 = 0
7) x2 – 7x – 120 = 0
8) 4x2 + 5x – 6 = 0
9) 6x2 + 5x – 1 = 0
10) 3x2 – 10x – 25 = 0
11) 7x2 – 16x + 9 = 0
12) x2 – 5ax + 6a2 = 0
me ayudan pliss
Respuestas
Respuesta dada por:
41
Para determinar las
raíces de las funciones cuadráticas se resuelve así! :
![Forma \ Polin\'omica\ \to ax^2+bx+c=0 \\ \\
1) Ecuaci\'on \ incompleta \quad\to x^2-3x= 0 \\ \\ Se \ aplica \ factor \
com\'un \\ \\ x^2-3x= 0 \\ \\ x(x-3) =0 \\ \\ x=0\qquad\qquad x= 3 \\ \\ Las \
ra\'ices\ son \ \boxed{ x_1=0\ y\ x_2= 3 } Forma \ Polin\'omica\ \to ax^2+bx+c=0 \\ \\
1) Ecuaci\'on \ incompleta \quad\to x^2-3x= 0 \\ \\ Se \ aplica \ factor \
com\'un \\ \\ x^2-3x= 0 \\ \\ x(x-3) =0 \\ \\ x=0\qquad\qquad x= 3 \\ \\ Las \
ra\'ices\ son \ \boxed{ x_1=0\ y\ x_2= 3 }](https://tex.z-dn.net/?f=Forma+%5C+Polin%5C%27omica%5C+%5Cto+ax%5E2%2Bbx%2Bc%3D0+%5C%5C+%5C%5C%0A1%29+Ecuaci%5C%27on+%5C+incompleta+%5Cquad%5Cto+x%5E2-3x%3D+0+%5C%5C+%5C%5C+Se+%5C+aplica+%5C+factor+%5C%0Acom%5C%27un+%5C%5C+%5C%5C+x%5E2-3x%3D+0+%5C%5C+%5C%5C+x%28x-3%29+%3D0+%5C%5C+%5C%5C+x%3D0%5Cqquad%5Cqquad+x%3D+3+%5C%5C+%5C%5C+Las+%5C%0Ara%5C%27ices%5C+son+%5C+%5Cboxed%7B+x_1%3D0%5C+y%5C+x_2%3D+3+%7D+)
------------------------------------
![2) 6x^2+42x= 0 \\ \\ Se \ aplica \ factor \
com\'un \\ \\ x^2-3x= 0 \\ \\ 6x(x+7) =0 \\ \\ 6x=0\to x= 0\qquad\qquad x+7= 0
\to x= -7\\ \\ Las \ ra\'ices\ son \ \boxed{ x_1=0\ y\ x_2= -7 } 2) 6x^2+42x= 0 \\ \\ Se \ aplica \ factor \
com\'un \\ \\ x^2-3x= 0 \\ \\ 6x(x+7) =0 \\ \\ 6x=0\to x= 0\qquad\qquad x+7= 0
\to x= -7\\ \\ Las \ ra\'ices\ son \ \boxed{ x_1=0\ y\ x_2= -7 }](https://tex.z-dn.net/?f=2%29+6x%5E2%2B42x%3D+0+%5C%5C+%5C%5C+Se+%5C+aplica+%5C+factor+%5C%0Acom%5C%27un+%5C%5C+%5C%5C+x%5E2-3x%3D+0+%5C%5C+%5C%5C+6x%28x%2B7%29+%3D0+%5C%5C+%5C%5C+6x%3D0%5Cto+x%3D+0%5Cqquad%5Cqquad+x%2B7%3D+0%0A%5Cto+x%3D+-7%5C%5C+%5C%5C+Las+%5C+ra%5C%27ices%5C+son+%5C+%5Cboxed%7B+x_1%3D0%5C+y%5C+x_2%3D+-7+%7D)
-----------------------------------
![3) x^2+ax= 0 \\ \\ Se \ aplica \
factor \ com\'un \\ \\ x^2+ax= 0 \\ \\ x(x+a) =0 \\ \\ x=0\qquad\qquad x+a=0\to
x=a \\ \\ Las \ ra\'ices\ son \ \boxed{ x_1=0\ y\ x_2= a } 3) x^2+ax= 0 \\ \\ Se \ aplica \
factor \ com\'un \\ \\ x^2+ax= 0 \\ \\ x(x+a) =0 \\ \\ x=0\qquad\qquad x+a=0\to
x=a \\ \\ Las \ ra\'ices\ son \ \boxed{ x_1=0\ y\ x_2= a }](https://tex.z-dn.net/?f=3%29+x%5E2%2Bax%3D+0+%5C%5C+%5C%5C+Se+%5C+aplica+%5C%0Afactor+%5C+com%5C%27un+%5C%5C+%5C%5C+x%5E2%2Bax%3D+0+%5C%5C+%5C%5C+x%28x%2Ba%29+%3D0+%5C%5C+%5C%5C+x%3D0%5Cqquad%5Cqquad+x%2Ba%3D0%5Cto%0Ax%3Da+%5C%5C+%5C%5C+Las+%5C+ra%5C%27ices%5C+son+%5C+%5Cboxed%7B+x_1%3D0%5C+y%5C+x_2%3D+a+%7D+)
----------------------------------
![4) x^2-18x+80= 0 \\ \\ Se \ aplica \ Bascara\to
x_{1\ y\ 2}= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} , entonces \\ \\ x^2-18x+80= 0
\\ \\ x_{1\ y\ 2}= \dfrac{-(-18)\pm \sqrt{(-18)^2-4(1)(80)} }{2(1)}\qquad a=
1\quad b=-18\quad c=80 \\ \\ x_{1\ y\ 2}= \dfrac{+18\pm \sqrt{324-320} }{2} \\
\\ x_{1\ y\ 2}= \dfrac{+18\pm \sqrt{4} }{2} \\ \\x_{1\ y\ 2}=\dfrac{18\pm2 }{2}
\\ \\ \\x_{1}=\dfrac{18+2 }{2} \qquad x_{1}=\dfrac{20 }{2} \qquad \boxed{x_1=
10} 4) x^2-18x+80= 0 \\ \\ Se \ aplica \ Bascara\to
x_{1\ y\ 2}= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} , entonces \\ \\ x^2-18x+80= 0
\\ \\ x_{1\ y\ 2}= \dfrac{-(-18)\pm \sqrt{(-18)^2-4(1)(80)} }{2(1)}\qquad a=
1\quad b=-18\quad c=80 \\ \\ x_{1\ y\ 2}= \dfrac{+18\pm \sqrt{324-320} }{2} \\
\\ x_{1\ y\ 2}= \dfrac{+18\pm \sqrt{4} }{2} \\ \\x_{1\ y\ 2}=\dfrac{18\pm2 }{2}
\\ \\ \\x_{1}=\dfrac{18+2 }{2} \qquad x_{1}=\dfrac{20 }{2} \qquad \boxed{x_1=
10}](https://tex.z-dn.net/?f=4%29+x%5E2-18x%2B80%3D+0+%5C%5C+%5C%5C+Se+%5C+aplica+%5C+Bascara%5Cto%0Ax_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B-b%5Cpm+%5Csqrt%7Bb%5E2-4ac%7D+%7D%7B2a%7D+%2C+entonces+%5C%5C+%5C%5C+x%5E2-18x%2B80%3D+0%0A%5C%5C+%5C%5C+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B-%28-18%29%5Cpm+%5Csqrt%7B%28-18%29%5E2-4%281%29%2880%29%7D+%7D%7B2%281%29%7D%5Cqquad+a%3D%0A1%5Cquad+b%3D-18%5Cquad+c%3D80+%5C%5C+%5C%5C+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B%2B18%5Cpm+%5Csqrt%7B324-320%7D+%7D%7B2%7D+%5C%5C%0A%5C%5C+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B%2B18%5Cpm+%5Csqrt%7B4%7D+%7D%7B2%7D+%5C%5C+%5C%5Cx_%7B1%5C+y%5C+2%7D%3D%5Cdfrac%7B18%5Cpm2+%7D%7B2%7D%0A%5C%5C+%5C%5C+%5C%5Cx_%7B1%7D%3D%5Cdfrac%7B18%2B2+%7D%7B2%7D+%5Cqquad+x_%7B1%7D%3D%5Cdfrac%7B20+%7D%7B2%7D+%5Cqquad+%5Cboxed%7Bx_1%3D%0A10%7D+)
![\\ \\ \\x_{2}=\dfrac{18-2 }{2} \qquad
x_{2}=\dfrac{16}{2} \qquad \boxed{x_2= 4} \\ \\ \\x_{2}=\dfrac{18-2 }{2} \qquad
x_{2}=\dfrac{16}{2} \qquad \boxed{x_2= 4}](https://tex.z-dn.net/?f=%5C%5C+%5C%5C+%5C%5Cx_%7B2%7D%3D%5Cdfrac%7B18-2+%7D%7B2%7D+%5Cqquad%0Ax_%7B2%7D%3D%5Cdfrac%7B16%7D%7B2%7D+%5Cqquad+%5Cboxed%7Bx_2%3D+4%7D)
-----------------------------------
![5) x^2-4x-96= 0 \\ \\ Se \ aplica \
Bascara\to x_{1\ y\ 2}= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} , entonces \\ \\ \\
\\ x_{1\ y\ 2}= \dfrac{-(-4)\pm \sqrt{(-4)^2-4(1)(-96)} }{2(1)}\qquad a= 1\quad
b=-4\quad c=-96 \\ \\ x_{1\ y\ 2}= \dfrac{+4\pm \sqrt{16+384} }{2} \\ \\ x_{1\
y\ 2}= \dfrac{+4\pm \sqrt{400} }{2} \\ \\x_{1\ y\ 2}=\dfrac{4\pm20 }{2} \\ \\
\\x_{1}=\dfrac{4+20 }{2} \qquad x_{1}=\dfrac{24 }{2} \qquad \boxed{x_1=6}\\ \\
\\x_{2}=\dfrac{4-20 }{2} \qquad x_{2}=\dfrac{-16 }{2} \qquad
\boxed{x_2=-8} 5) x^2-4x-96= 0 \\ \\ Se \ aplica \
Bascara\to x_{1\ y\ 2}= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} , entonces \\ \\ \\
\\ x_{1\ y\ 2}= \dfrac{-(-4)\pm \sqrt{(-4)^2-4(1)(-96)} }{2(1)}\qquad a= 1\quad
b=-4\quad c=-96 \\ \\ x_{1\ y\ 2}= \dfrac{+4\pm \sqrt{16+384} }{2} \\ \\ x_{1\
y\ 2}= \dfrac{+4\pm \sqrt{400} }{2} \\ \\x_{1\ y\ 2}=\dfrac{4\pm20 }{2} \\ \\
\\x_{1}=\dfrac{4+20 }{2} \qquad x_{1}=\dfrac{24 }{2} \qquad \boxed{x_1=6}\\ \\
\\x_{2}=\dfrac{4-20 }{2} \qquad x_{2}=\dfrac{-16 }{2} \qquad
\boxed{x_2=-8}](https://tex.z-dn.net/?f=5%29+x%5E2-4x-96%3D+0+%5C%5C+%5C%5C+Se+%5C+aplica+%5C%0ABascara%5Cto+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B-b%5Cpm+%5Csqrt%7Bb%5E2-4ac%7D+%7D%7B2a%7D+%2C+entonces+%5C%5C+%5C%5C+%5C%5C%0A%5C%5C+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B-%28-4%29%5Cpm+%5Csqrt%7B%28-4%29%5E2-4%281%29%28-96%29%7D+%7D%7B2%281%29%7D%5Cqquad+a%3D+1%5Cquad%0Ab%3D-4%5Cquad+c%3D-96+%5C%5C+%5C%5C+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B%2B4%5Cpm+%5Csqrt%7B16%2B384%7D+%7D%7B2%7D+%5C%5C+%5C%5C+x_%7B1%5C%0Ay%5C+2%7D%3D+%5Cdfrac%7B%2B4%5Cpm+%5Csqrt%7B400%7D+%7D%7B2%7D+%5C%5C+%5C%5Cx_%7B1%5C+y%5C+2%7D%3D%5Cdfrac%7B4%5Cpm20+%7D%7B2%7D+%5C%5C+%5C%5C%0A%5C%5Cx_%7B1%7D%3D%5Cdfrac%7B4%2B20+%7D%7B2%7D+%5Cqquad+x_%7B1%7D%3D%5Cdfrac%7B24+%7D%7B2%7D+%5Cqquad+%5Cboxed%7Bx_1%3D6%7D%5C%5C+%5C%5C%0A%5C%5Cx_%7B2%7D%3D%5Cdfrac%7B4-20+%7D%7B2%7D+%5Cqquad+x_%7B2%7D%3D%5Cdfrac%7B-16+%7D%7B2%7D+%5Cqquad%0A%5Cboxed%7Bx_2%3D-8%7D)
-----------------------------------
![6) x^2-17x+52= 0 \\ \\ Se \ aplica \
Bascara\to x_{1\ y\ 2}= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} , entonces \\ \\ \\
\\ x_{1\ y\ 2}= \dfrac{-(-17)\pm \sqrt{(-17)^2-4(1)(52)} }{2(1)}\qquad a=
1\quad b=-17\quad c=52 \\ \\ x_{1\ y\ 2}= \dfrac{+17\pm \sqrt{289-208} }{2} \\
\\ x_{1\ y\ 2}= \dfrac{17\pm \sqrt{81} }{2} \\ \\x_{1\ y\ 2}=\dfrac{17\pm9 }{2}
\\ \\ \\x_{1}=\dfrac{17+9 }{2} \qquad x_{1}=\dfrac{26 }{2} \qquad
\boxed{x_1=13}\\ \\ \\x_{2}=\dfrac{17-9 }{2} \qquad x_{2}=\dfrac{8 }{2} \qquad
\boxed{x_2=4} 6) x^2-17x+52= 0 \\ \\ Se \ aplica \
Bascara\to x_{1\ y\ 2}= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} , entonces \\ \\ \\
\\ x_{1\ y\ 2}= \dfrac{-(-17)\pm \sqrt{(-17)^2-4(1)(52)} }{2(1)}\qquad a=
1\quad b=-17\quad c=52 \\ \\ x_{1\ y\ 2}= \dfrac{+17\pm \sqrt{289-208} }{2} \\
\\ x_{1\ y\ 2}= \dfrac{17\pm \sqrt{81} }{2} \\ \\x_{1\ y\ 2}=\dfrac{17\pm9 }{2}
\\ \\ \\x_{1}=\dfrac{17+9 }{2} \qquad x_{1}=\dfrac{26 }{2} \qquad
\boxed{x_1=13}\\ \\ \\x_{2}=\dfrac{17-9 }{2} \qquad x_{2}=\dfrac{8 }{2} \qquad
\boxed{x_2=4}](https://tex.z-dn.net/?f=6%29+x%5E2-17x%2B52%3D+0+%5C%5C+%5C%5C+Se+%5C+aplica+%5C%0ABascara%5Cto+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B-b%5Cpm+%5Csqrt%7Bb%5E2-4ac%7D+%7D%7B2a%7D+%2C+entonces+%5C%5C+%5C%5C+%5C%5C%0A%5C%5C+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B-%28-17%29%5Cpm+%5Csqrt%7B%28-17%29%5E2-4%281%29%2852%29%7D+%7D%7B2%281%29%7D%5Cqquad+a%3D%0A1%5Cquad+b%3D-17%5Cquad+c%3D52+%5C%5C+%5C%5C+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B%2B17%5Cpm+%5Csqrt%7B289-208%7D+%7D%7B2%7D+%5C%5C%0A%5C%5C+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B17%5Cpm+%5Csqrt%7B81%7D+%7D%7B2%7D+%5C%5C+%5C%5Cx_%7B1%5C+y%5C+2%7D%3D%5Cdfrac%7B17%5Cpm9+%7D%7B2%7D%0A%5C%5C+%5C%5C+%5C%5Cx_%7B1%7D%3D%5Cdfrac%7B17%2B9+%7D%7B2%7D+%5Cqquad+x_%7B1%7D%3D%5Cdfrac%7B26+%7D%7B2%7D+%5Cqquad%0A%5Cboxed%7Bx_1%3D13%7D%5C%5C+%5C%5C+%5C%5Cx_%7B2%7D%3D%5Cdfrac%7B17-9+%7D%7B2%7D+%5Cqquad+x_%7B2%7D%3D%5Cdfrac%7B8+%7D%7B2%7D+%5Cqquad%0A%5Cboxed%7Bx_2%3D4%7D)
-------------------------------
![7) x^2-7x-120= 0 \\ \\ Se \ aplica \
Bascara\to x_{1\ y\ 2}= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} , entonces \\ \\ \\
\\ x_{1\ y\ 2}= \dfrac{-(-7)\pm \sqrt{(-7)^2-4(1)(-120)} }{2(1)}\qquad a=
1\quad b=-7\quad c=-120 \\ \\ x_{1\ y\ 2}= \dfrac{+7\pm \sqrt{49+480} }{2} \\
\\ x_{1\ y\ 2}= \dfrac{7\pm \sqrt{529} }{2} \\ \\x_{1\ y\ 2}=\dfrac{7\pm23 }{2}
\\ \\ \\x_{1}=\dfrac{7+23 }{2} \qquad x_{1}=\dfrac{30 }{2} \qquad
\boxed{x_1=15}\\ \\ \\x_{2}=\dfrac{7-23 }{2} \qquad x_{2}=\dfrac{-16 }{2}
\qquad \boxed{x_2=-8} 7) x^2-7x-120= 0 \\ \\ Se \ aplica \
Bascara\to x_{1\ y\ 2}= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} , entonces \\ \\ \\
\\ x_{1\ y\ 2}= \dfrac{-(-7)\pm \sqrt{(-7)^2-4(1)(-120)} }{2(1)}\qquad a=
1\quad b=-7\quad c=-120 \\ \\ x_{1\ y\ 2}= \dfrac{+7\pm \sqrt{49+480} }{2} \\
\\ x_{1\ y\ 2}= \dfrac{7\pm \sqrt{529} }{2} \\ \\x_{1\ y\ 2}=\dfrac{7\pm23 }{2}
\\ \\ \\x_{1}=\dfrac{7+23 }{2} \qquad x_{1}=\dfrac{30 }{2} \qquad
\boxed{x_1=15}\\ \\ \\x_{2}=\dfrac{7-23 }{2} \qquad x_{2}=\dfrac{-16 }{2}
\qquad \boxed{x_2=-8}](https://tex.z-dn.net/?f=7%29+x%5E2-7x-120%3D+0+%5C%5C+%5C%5C+Se+%5C+aplica+%5C%0ABascara%5Cto+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B-b%5Cpm+%5Csqrt%7Bb%5E2-4ac%7D+%7D%7B2a%7D+%2C+entonces+%5C%5C+%5C%5C+%5C%5C%0A%5C%5C+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B-%28-7%29%5Cpm+%5Csqrt%7B%28-7%29%5E2-4%281%29%28-120%29%7D+%7D%7B2%281%29%7D%5Cqquad+a%3D%0A1%5Cquad+b%3D-7%5Cquad+c%3D-120+%5C%5C+%5C%5C+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B%2B7%5Cpm+%5Csqrt%7B49%2B480%7D+%7D%7B2%7D+%5C%5C%0A%5C%5C+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B7%5Cpm+%5Csqrt%7B529%7D+%7D%7B2%7D+%5C%5C+%5C%5Cx_%7B1%5C+y%5C+2%7D%3D%5Cdfrac%7B7%5Cpm23+%7D%7B2%7D%0A%5C%5C+%5C%5C+%5C%5Cx_%7B1%7D%3D%5Cdfrac%7B7%2B23+%7D%7B2%7D+%5Cqquad+x_%7B1%7D%3D%5Cdfrac%7B30+%7D%7B2%7D+%5Cqquad%0A%5Cboxed%7Bx_1%3D15%7D%5C%5C+%5C%5C+%5C%5Cx_%7B2%7D%3D%5Cdfrac%7B7-23+%7D%7B2%7D+%5Cqquad+x_%7B2%7D%3D%5Cdfrac%7B-16+%7D%7B2%7D%0A%5Cqquad+%5Cboxed%7Bx_2%3D-8%7D)
---------------------------
![8) 4x^2+5x-6= 0 \\ \\ Se \ aplica \
Bascara\to x_{1\ y\ 2}= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} , entonces \\ \\ \\
\\ x_{1\ y\ 2}= \dfrac{-(5)\pm \sqrt{(5)^2-4(4)(-6)} }{2(4)}\qquad a= 4\quad
b=5\quad c=-6 \\ \\ x_{1\ y\ 2}= \dfrac{-5\pm \sqrt{25+96} }{8} \\ \\ x_{1\ y\
2}= \dfrac{-5\pm \sqrt{121} }{8} \\ \\x_{1\ y\ 2}=\dfrac{-5\pm11 }{8} \\ \\
\\x_{1}=\dfrac{-5+11 }{8} \qquad x_{1}=\dfrac{6}{8} \qquad \boxed{x_1=
\frac{3}{4} }\\ \\ \\x_{2}=\dfrac{-5-11}{8} \qquad x_{2}=\dfrac{-16 }{8} \qquad
\boxed{x_2=-2} 8) 4x^2+5x-6= 0 \\ \\ Se \ aplica \
Bascara\to x_{1\ y\ 2}= \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} , entonces \\ \\ \\
\\ x_{1\ y\ 2}= \dfrac{-(5)\pm \sqrt{(5)^2-4(4)(-6)} }{2(4)}\qquad a= 4\quad
b=5\quad c=-6 \\ \\ x_{1\ y\ 2}= \dfrac{-5\pm \sqrt{25+96} }{8} \\ \\ x_{1\ y\
2}= \dfrac{-5\pm \sqrt{121} }{8} \\ \\x_{1\ y\ 2}=\dfrac{-5\pm11 }{8} \\ \\
\\x_{1}=\dfrac{-5+11 }{8} \qquad x_{1}=\dfrac{6}{8} \qquad \boxed{x_1=
\frac{3}{4} }\\ \\ \\x_{2}=\dfrac{-5-11}{8} \qquad x_{2}=\dfrac{-16 }{8} \qquad
\boxed{x_2=-2}](https://tex.z-dn.net/?f=8%29+4x%5E2%2B5x-6%3D+0+%5C%5C+%5C%5C+Se+%5C+aplica+%5C%0ABascara%5Cto+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B-b%5Cpm+%5Csqrt%7Bb%5E2-4ac%7D+%7D%7B2a%7D+%2C+entonces+%5C%5C+%5C%5C+%5C%5C%0A%5C%5C+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B-%285%29%5Cpm+%5Csqrt%7B%285%29%5E2-4%284%29%28-6%29%7D+%7D%7B2%284%29%7D%5Cqquad+a%3D+4%5Cquad%0Ab%3D5%5Cquad+c%3D-6+%5C%5C+%5C%5C+x_%7B1%5C+y%5C+2%7D%3D+%5Cdfrac%7B-5%5Cpm+%5Csqrt%7B25%2B96%7D+%7D%7B8%7D+%5C%5C+%5C%5C+x_%7B1%5C+y%5C%0A2%7D%3D+%5Cdfrac%7B-5%5Cpm+%5Csqrt%7B121%7D+%7D%7B8%7D+%5C%5C+%5C%5Cx_%7B1%5C+y%5C+2%7D%3D%5Cdfrac%7B-5%5Cpm11+%7D%7B8%7D+%5C%5C+%5C%5C%0A%5C%5Cx_%7B1%7D%3D%5Cdfrac%7B-5%2B11+%7D%7B8%7D+%5Cqquad+x_%7B1%7D%3D%5Cdfrac%7B6%7D%7B8%7D+%5Cqquad+%5Cboxed%7Bx_1%3D%0A%5Cfrac%7B3%7D%7B4%7D+%7D%5C%5C+%5C%5C+%5C%5Cx_%7B2%7D%3D%5Cdfrac%7B-5-11%7D%7B8%7D+%5Cqquad+x_%7B2%7D%3D%5Cdfrac%7B-16+%7D%7B8%7D+%5Cqquad%0A%5Cboxed%7Bx_2%3D-2%7D)
------------------------------------
-----------------------------------
----------------------------------
-----------------------------------
-----------------------------------
-------------------------------
---------------------------
----------------------------------
---------------------------------
--------------------------------
Te agrego el 11) y el 12) en adjuntos porque el lugar de respuesta no alcanzo para hacerlo acá
Espero que te sirva, salu2!!!!
Adjuntos:
Preguntas similares
hace 6 años
hace 6 años
hace 6 años
hace 9 años
hace 9 años
hace 9 años
hace 9 años
hace 9 años