Question

1) 2(x-2)+5=3x+2

2) (x+3)-(3x+3)=2x-1

3) 4x + 1= 3(x-1)+6

4) 6- (8x+1)=2x-(2-3x)

Answer 1

1) 2(x-2)+5=3x+2
$2x-4+5=3x+2 \\ 2x-3x=2+4-5 \\ -x=6-5 \\ -x=1 \\ x=-1$

2)(x+3)-(3x+3)=2x-1
 $x+3-3x-3=2x-1 \\ x-3x-2x=-1-3+3 \\ x-5x=-1 \\ -4x=-1 \\ x= \frac{-1}{-4} \\ x= \frac{1}{4}$(x+3)-(3x+3)=2x-1

3) 4x + 1= 3(x-1)+6
$4x+1=3x-3+6 \\ 4x-3x=-3+6-1 \\ x=+6-4 \\ x=2$

4) 6- (8x+1)=2x-(2-3x)
$6-8x-1=2x-2+3x \\ -8x-2x-3x=-2-6+1 \\ -13x=-8+1 \\ -13x=-7 \\ x= \frac{-7}{-13} \\ x= \frac{7}{13}$