Respuestas
Respuesta dada por:
6
Primero factorizas cada número
![\sqrt{80}-2 \sqrt{252}+3 \sqrt{405} = \sqrt{80}-2 \sqrt{252}+3 \sqrt{405} =](https://tex.z-dn.net/?f=+%5Csqrt%7B80%7D-2+%5Csqrt%7B252%7D%2B3++%5Csqrt%7B405%7D+%3D+)
entonces
![80 = 2^{4}*5 80 = 2^{4}*5](https://tex.z-dn.net/?f=80+%3D++2%5E%7B4%7D%2A5+)
![252 = 2^{2}*3^{2}* 7 252 = 2^{2}*3^{2}* 7](https://tex.z-dn.net/?f=252+%3D++2%5E%7B2%7D%2A3%5E%7B2%7D%2A+7)
![405 = 3^{4}*5 405 = 3^{4}*5](https://tex.z-dn.net/?f=405+%3D++3%5E%7B4%7D%2A5+)
reemplazamos
![\sqrt{2^{4}*5}-2 \sqrt{ 2^{2}*3^{2}*5}+3 \sqrt{ 3^{4}*5} = \sqrt{2^{4}*5}-2 \sqrt{ 2^{2}*3^{2}*5}+3 \sqrt{ 3^{4}*5} =](https://tex.z-dn.net/?f=+%5Csqrt%7B2%5E%7B4%7D%2A5%7D-2+%5Csqrt%7B+2%5E%7B2%7D%2A3%5E%7B2%7D%2A5%7D%2B3++%5Csqrt%7B+3%5E%7B4%7D%2A5%7D+%3D+)
Distribuimos las raíces
![\sqrt{2^{4}} \sqrt{5} -2 \sqrt{ 2^{2}} \sqrt{3^{2}} \sqrt{5}+3 \sqrt{ 3^{4}} \sqrt{5} = \sqrt{2^{4}} \sqrt{5} -2 \sqrt{ 2^{2}} \sqrt{3^{2}} \sqrt{5}+3 \sqrt{ 3^{4}} \sqrt{5} =](https://tex.z-dn.net/?f=+%5Csqrt%7B2%5E%7B4%7D%7D+%5Csqrt%7B5%7D+-2+%5Csqrt%7B+2%5E%7B2%7D%7D+%5Csqrt%7B3%5E%7B2%7D%7D+%5Csqrt%7B5%7D%2B3++%5Csqrt%7B+3%5E%7B4%7D%7D+%5Csqrt%7B5%7D++%3D+)
resolvemos
![2^{2} \sqrt{5} -2*2*3 \sqrt{5}+3*3^{2} \sqrt{5} = 2^{2} \sqrt{5} -2*2*3 \sqrt{5}+3*3^{2} \sqrt{5} =](https://tex.z-dn.net/?f=2%5E%7B2%7D+%5Csqrt%7B5%7D+-2%2A2%2A3+%5Csqrt%7B5%7D%2B3%2A3%5E%7B2%7D+%5Csqrt%7B5%7D++%3D+)
![4 \sqrt{5} - 12 \sqrt{5}+27 \sqrt{5} = 4 \sqrt{5} - 12 \sqrt{5}+27 \sqrt{5} =](https://tex.z-dn.net/?f=+4+%5Csqrt%7B5%7D+-+12+%5Csqrt%7B5%7D%2B27+%5Csqrt%7B5%7D++%3D+)
sumamos y restamos
![19 \sqrt{5} 19 \sqrt{5}](https://tex.z-dn.net/?f=+19+%5Csqrt%7B5%7D)
Espero que te sirva, salu2!!!!
entonces
reemplazamos
Distribuimos las raíces
resolvemos
sumamos y restamos
Espero que te sirva, salu2!!!!
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