Question

1 3¹⁰•3³•3⁶ ________ 3⁹•3⁷
respondan doy

2 25⁵•25¹¹
_______
25⁷°25⁸


3 –5
_
2​

Answer 1

$\frac{3^{10} . 3^{3} . 3^{6} }{3^{9} .3^{7} } \\\\\frac{3^{10+3+7} }{3^{9+7} } \\\\\frac{3^{19} }{3x^{16} } \\\\3^{19-16}\\\\3x^{3} \\\\27$

$\frac{25^{5} . 25^{11} }{25^{7} 25^{8} } \\\\\frac{25^{5+11} }{25^{7 + 8} }\\\\\frac{25^{16} }{25^{15} } \\\\25^{16-15}\\\\2$

Eternamente axllxa