Question

aploca las propiedades y calcula la potencia a y b
A) (10/3)^3*0,3^-1
B) 0,25^4÷(1/4)^2=​

Answer 1

(10/3)^3*0,3^-1

$(\frac{10}{3})^{^{3} } (0,3)^{-1} \\\\(\frac{10}{3})^{^{3} } (\frac{3}{10} )^{-1}\\\\(\frac{10}{3})^{^{3} } (\frac{10}{3} )\\\\(\frac{10}{3})^{^{3+1}}\\\\(\frac{10}{3})^{^{4}}\\\\\frac{10000}{81}$

0,25^4÷(1/4)^2

$(0,25)^{4} : (\frac{1}{4})^{^{2} } \\\\(\frac{25}{100})^{^{4} } :(\frac{1}{4})^{^{2} } \\\\(\frac{1}{4})^{^{4} } :(\frac{1}{4})^{^{2} }\\\\ (\frac{1}{4})^{^{4-2} } \\\\(\frac{1}{4})^{^{2} }\\\\\frac{1}{16}$

Eternamente axllxa