Question

ayuda xfavor.........​

Answer 1

Respuesta:

f (x) = 4 - 2$x^{2}$ + $x^{4}$

f (0) = 4 - 2 * $0^{2}$ + $0^{4}$

f (0) = 4

f (1) = 4 - 2 * $1^{2}$ + $1^{4}$

f (1) = 4 - 2 * 1 + 1

f (1) = 4 - 2 + 1 = 3

f (-1) = 4 - 2 * $(-1)^{2}$ + $(-1)^{4}$

f (-1) = 4 - 2 * 1 + 1

f (-1) = 4 - 2 + 1 = 3

f (2) = 4 - 2 * $2^{2}$ + $2^{4}$

f (2) = 4 - 2 * 4 + 16

f (2) = 4 - 8 + 16 = 12

f (-2) = 4 - 2 * $(-2)^{2}$ + $(-2)^{4}$

f (-2) = 4 - 2 * 4 + 16

f (-2) = 4 - 8 + 16 = 12

Explicación: