Question

cuanto es x² + 4px + p + 2 =0

Answer 1

Respuesta:

$x≠ - \frac{1}{4}$

Explicación paso a paso:

${x}^{2} + 4px + p + 2 - {x}^{2} = 0 - {x}^{2}$

$4px + p + 2 = - {x}^{2}$

$4px + p + 2 - 2 = - {x}^{2} - 2$

$4px + p = - {x}^{2} - 2$

$p(4x + 1) = - {x}^{2} - 2$

$\frac{p(4x + 1)}{4x + 1} = \frac{ {x}^{2} }{4x + 1} - \frac{2}{4x + 1} = x ≠ - \frac{1}{4}$

$p = \frac{ - {x}^{2} - 2 }{4x + 1} = x ≠ - \frac{1}{4}$