Question

(1,5x^2y-0,4xy^3) (-0,3xy)



pls

Answer 1

$(1.5 x^{2} y - 0.4x y^{3})(-0.3xy)$

$( \frac{15}{10} x^{2} y- \frac{4}{10}x y^{3})(- \frac{3}{10} xy)$

$- \frac{45}{100} x^{3} y^{2} + \frac{12}{100} x^{2} y^{4}$

$- \frac{3 x^{2} y^{2}(15x-4 y^{2}) }{100}$