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consider that for any triangle the sum of two of its sides must be greater than the measure of the third side then ab + bc = AC How does it equal 10 the minimum integer value of the sum must be 11 we have several pairs of measures that add up
10 + 1 = 10
9 + 2 = 10
8 + 3 = 10
7 + 4 = 10
6+ 5 = 10
in all cases the sum of the sides, that is, the perimeter is equal to 21 Then the minimum integer value of the perimeter of the tangular region abc. is 21
abiglz2005:
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