Question

Aiuda Xfa xCccccccccccccccccccccccc​

Answer 1

ぉしえんとのせばygらしあjjjjjjjjj

Answer 2

Respuesta:

♫HOLA♫

$\frac{(9^{-n})^{5} .(9^{6})^{n} .(9^{7})^{n} }{(9^{3})n^{2} .(9^{n} )^{5} } =\frac{9^{-5n} .9^{6n}.9^{7n} }{9^{3n} .9^{5n} } =\frac{9^{-5n+6n+7n} }{9^{3n+5n} } =\frac{9^{8n} }{9^{8n} } =1$

Rpta: sale 1

Explicación paso a paso:

Espero que te ayude :)