Question

ayuda pliss con resolucion

Answer 1

Respuesta:

-2

Explicación paso a paso:

$x+\frac{1}{x}=\sqrt{2}$

$(x+\frac{1}{x})^{2} =(\sqrt{2})^{2}$

$x^{2} +2\frac{x}{x}+\frac{1}{x^{2} } =2$

$x^{2} +2+\frac{1}{x^{2} } =2$

$x^{2} +\frac{1}{x^{2} } =2-2$

$x^{2} +\frac{1}{x^{2} } =0$

$(x^{2} +\frac{1}{x^{2} })^{2} =0$

$x^{4} +2\frac{x^{2} }{x^{2} }+ \frac{1}{x^{4} } =0$

$x^{4} +2+ \frac{1}{x^{4} } =0$

$x^{4} + \frac{1}{x^{4} } =-2$