Question

(4p – 2q + 5)(p + 4q) 4 (2m + 5n – 1)
ayudenme con esta por favor

Answer 1

Respuesta:

$\left(4p\:-\:2q\:+\:5\right)\left(p\:+\:4q\right)\:4\:\left(2m\:+\:5n\:-\:1\right)$

$4\left(4p-2q+5\right)\left(p+4q\right)\left(2m+5n-1\right)$

Desarrollamos $4\left(p+4q\right)$

= $4p+16q$

$\left(4p+16q\right)\left(4p-2q+5\right)\left(2m+5n-1\right)$

Desarrollamos $\left(4p+16q\right)\left(4p-2q+5\right)$

= $16p^2+56pq+20p-32q^2+80q$

$\left(16p^2+56pq+20p-32q^2+80q\right)\left(2m+5n-1\right)$

Desarrollamos $\left(16p^2+56pq+20p-32q^2+80q\right)\left(2m+5n-1\right)$

$16p^2\cdot \:2m+16p^2\cdot \:5n+16p^2\left(-1\right)+56pq\cdot \:2m+56pq\cdot \:5n+56pq\left(-1\right)+20p\cdot \:2m+20p\cdot \:5n+20p\left(-1\right)-32q^2\cdot \:2m-32q^2\cdot \:5n-32q^2\left(-1\right)+80q\cdot \:2m+80q\cdot \:5n+80q\left(-1\right)$

Simplificamos$16p^2\cdot \:2m+16p^2\cdot \:5n+16p^2\left(-1\right)+56pq\cdot \:2m+56pq\cdot \:5n+56pq\left(-1\right)+20p\cdot \:2m+20p\cdot \:5n+20p\left(-1\right)-32q^2\cdot \:2m-32q^2\cdot \:5n-32q^2\left(-1\right)+80q\cdot \:2m+80q\cdot \:5n+80q\left(-1\right)$

= $32mp^2+80p^2n-16p^2+112mpq+280npq-56pq+40mp+100np-20p-64mq^2-160nq^2+32q^2+160mq+400nq-80$

Buenas noches