Question

$\frac{6}{ x^{2} -3x} = \frac{12}{x} + \frac{1}{x-3}$

Answer 1

$\frac{6}{ x^{2} -3x} = \frac{12}{x} + \frac{1}{x-3}$

Factorizando y efectuando
$\frac{6}{x(x-3)} = \frac{12(x-3)+x}{x(x-3)} \\ \\ 6=12x-36+x \\ \\ 6+36=13x \\ \\ 13x=42 \\ \\ x= \frac{42}{13}$