Question

Dados los conjuntos A y B se conocen:
n(A) – n(B) = 2
n(A - B) = n(A’)
n[P(A’)] = 128
n[U] = 20
Hallar n[P(B - A)]

Answer 1

Respuesta:

n(A)=7

n(B)=8

n(A∩B)=5

n[P(AUB)]=2^10=1024

Explicación paso a paso:

n[P(A)]=128 = 2^n(A)=2^7 entonces n(A)=7

n[P(B)]=256 = Si  2^n(B)=2^8 entonces n(B)=8

n[P(A∩B)]=32 =  2^n(A∩B)=2^5 entonces n(A∩B)=5

n(AUB)=10.....Por lo tanto n[P(AUB)]=2^10=1024