Question

lim 4x²-8x+4/x-1
x—1. ​

Answer 1

Explicación paso a paso:

$lim \frac{(4 {x}^{2} - 8x + 4) }{x - 1} \\ lim \frac{4( {x}^{2} - 2x + 1) }{x - 1} \\ lim \frac{4 {(x - 1)}^{2} }{x - 1} \\ lim \: 4(x - 1) \\ para \: x = 1 \\ 4(1 - 1) = 0$