Question

calcular la distancia mn . si m(-5,2)n(3, -2) xfaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa ayuda es para hoy

Answer 1

Respuesta:

$\boxed{\mathbf{d=4\sqrt{5}\,u}}$

Explicación paso a paso:

Puntos:

$m=(-5,2)\,\,,n=(3,-2)$

Formula:

$d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

Desarrollo:

$d=\sqrt{(3-(-5))^{2}+(-2-2)^{2}}=\sqrt(8^{2}+(-4)^{2}}=\\\\=\sqrt{64+16}=\sqrt{80}=\\\\=\sqrt{(16)(5)}=\sqrt{16}\sqrt{5}=\\\\=4\sqrt{5}\,u$