Question

9x10 -5÷5+7=

7+3x6-64÷2=

9-√81+15²÷25=

107-8x3x(18-6÷√9)=

45x{81÷3+12x[14-√25-(6-15÷3)]}=

PORFAVOR PONGAN PROCEDIMIENTO :)))​

Answer 1

Respuesta:

1.

$9x10\:-5\div 5+7\\\\\frac{9x^{10}-5}{5+7}\\\\=\frac{9x^{10}-5}{12}$

2.

$7+3x6-64\div 2\\\\\frac{7+3x^6-64}{2}\\\\=\frac{3x^6-57}{2}$

3.

$9-\sqrt{8}1+15^{2} \div 25\\\\\frac{9-\sqrt{8}\cdot \:1+15^2}{25}\\\\=\frac{234-\sqrt{8}}{25}\\\\=\frac{234-2\sqrt{2}}{25}$

4.

$107-8x3x\left(18-6\div \sqrt{9}\right)\\\\107-8x^3x\left(18-\frac{6}{\sqrt{9}}\right)\\\\=107-128x^4\\\\=-128x^4+107$

5.

$45x\left\{81\div \:3+12x\left[14-\sqrt{2}5-\left(6-15\div \:3\right)\right]\right\}\\\\5x\left(\frac{81}{3}+12x\left(14-\sqrt{2}\cdot \:5-\left(6-\frac{15}{3}\right)\right)\right)\\\\=45x\left(12\left(13-5\sqrt{2}\right)x+27\right)$

Answer 2

Respuesta:

eso en que grado vas o que

Explicación paso a paso: