Question

Calcule el volumen que ocupan 15 gramos de O2, considerado como un gas ideal, a 3 atmósferas de presión y 25 °C.lo resolverlo y mostrar los cálculos.

Answer 1

m = 15 g de O2

P =  3 atm

T = 25 + 273 = 298 K

Mm O2 = 32 g/mol

mol = masa/Mm

mol = 15 g/ 32 g/mol = 0.468 mol

R = 0.0821 (atm L / mol K)

P x V = n x R x T

V = 0.468 mol x 0.0821 (atm L / mol K)  x  298 K
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                          3 atm

V = 3.816 L