Question

Calcular la pendiente de la recta tangente:
f(x)=2x²+3x+5 x=1

Answer 1

f(x)=2x²+3x+5

x= 1

y= x^1/2

dy/dx = 1/2 x^-1/2 = 1/2 √x

1 / 2√1 = 1/ 2 (1)= 1/2

Pendiente = 1/2