Question

resolver es para hoy

Answer 1

Respuesta:

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$5x^2+4x-1=0$

$x_{1,\:2}=\frac{-4\pm \sqrt{4^2-4\cdot \:5\left(-1\right)}}{2\cdot \:5}$

$\sqrt{4^2-4\cdot \:5\left(-1\right)}\\=\sqrt{4^2+4\cdot \:5\cdot \:1}\\=\sqrt{4^2+20}\\=\sqrt{16+20}\\=\sqrt{36}\\=6$

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$x_{1,\:2}=\frac{-4\pm \:6}{2\cdot \:5}$

$x_1=\frac{-4+6}{2\cdot \:5},\:x_2=\frac{-4-6}{2\cdot \:5}$

$\frac{-4+6}{2\cdot \:5}$

$=\frac{2}{2\cdot \:5}$

$=\frac{2}{10}$

$=\frac{1}{5}$

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$x=\frac{-4-6}{2\cdot \:5}$

$\frac{-4+6}{2\cdot \:5}$

$=\frac{-10}{2\cdot \:5}$

$=\frac{-10}{10}$

$=-1$

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$x=\frac{1}{5},\:x=-1$

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