Question

( 4a⁴-2a²+a-5 )÷ ( a+2)​

Answer 1

Respuesta:

Explicación paso a paso:

$\frac{\left(4a^4-2a^2+a-5\right)}{\left(a+2\right)}$

$=4a^3+\frac{-8a^3-2a^2+a-5}{a+2}$

$=4a^3-8a^2+\frac{14a^2+a-5}{a+2}$

$=4a^3-8a^2+14a+\frac{-27a-5}{a+2}$

$=4a^3-8a^2+14a-27+\frac{49}{a+2}$