Question

a) a- 3a - 10 = (a -_)(_+2)
b) c2 +7c+ 12 = (c+_)(_+4)
c) y2 - 22y + 120 = (y -12)(_-_)​

Answer 1

a) a2- 3a - 10 = (a -_5)(_+2)

b) c2 +7c+ 12 = (c+_3)(_c+4)

c) y2 - 22y + 120 = (y -12)(_y-_10)