Question

(x-1)(x+1)(x^2 + 2) =??? ​

Answer 1

ΗΘΙΑ

procedimiento :

$(x-1)(x+1)(x^2 + 2) =$

$=x^{2} x^{2} +x^{2} .2-1.x^{2} -1.2$

$=x^{4} +x^{2} -2$

salu2!!

Answer 2

Respuesta:

(x−1)(x+1)(x

2

+2)=

=x^{2} x^{2} +x^{2} .2-1.x^{2} -1.2=x

2

x

2

+x

2

.2−1.x

2

−1.2

=x^{4} +x^{2} -2=x

4

+x

2

−2