Question

ayúdenme doy de todo es examen porfavor​

Answer 1

Respuesta:

$\sqrt{\frac{5^{2} +10^{2} }{2^{3}-\sqrt{9} }+11 } =\sqrt{\frac{25+100}{8-3 }+11 }=\sqrt{\frac{125}{5 }+11 }=\sqrt{25+11 }=\sqrt{36} =6$

$(\sqrt[3]{125} +2^{2} )^{2} -(\sqrt{18} )^{0} =(5+4)^{2}-1=81-1=80\\\sqrt{9^{2} +12^{2} } +\sqrt{3^{2} +4^{2} } =\sqrt{15^{2} } +\sqrt{5^{2} } =15+5=20$

$\sqrt{\sqrt{625} +5^{2} +\sqrt{25^{2} }+2^{3} -2 } =\sqrt{25 +25 +25+8 -2 } =\sqrt{81 } =9$

$\sqrt{3^{2} +2^{3} +5^{2} +12^{0} +4^{2} +5} =\sqrt{50+8+1+5} =\sqrt{64} =8$$\sqrt{4\sqrt{81} } +\sqrt[3]{1+\sqrt{49} } =\sqrt{36} +\sqrt[3]{8} =6+2=8$$\sqrt{8^{2} } +\sqrt[3]{10^{3} } -\sqrt[7]{6^{7} } =8+10-6=12$

$\sqrt{\frac{\sqrt[3]{125}+\sqrt{64} +\sqrt{144} }{\sqrt[3]{125}-\sqrt{16} } } =\sqrt{\frac{5+8+12}{5-4} } =\sqrt{25} =5$