Question

I. Resolver cada suma por diferencia 1. (x-2)(x+2) 2. (a +3)(a -3) 4. (3x+2)(3x - 2) 5. (3x + y)(3x - y) 7. (7a -b)(7a +b) 8. (5x+10y)(5x-10y) 10. (7a? +2b)(7a- 26) II. Resolver cada cuadrado de binomio 1. (x+4)? 2. (3x + 2) 4. (p+57) 5. (a + 2b) 7. (5x + 3y)? 8. (a – 3b)? 10. (6x - 5y)? 11. (x²-5) III. Resolver cada producto 1. (x-2)(x+1) 2. (a +3)(a -2) 4. (4x + 2)(x - 5) 5. (5x-2)(5x-2) 7. (4a - b)(3a + b) 8. (2x + 5y)(5x + y) 10. (x-3) 11. (Ta’ - b)(3a - 2b) doy corona ​

Answer 1

Respuesta:

Explicación paso a paso:

I diferencia de cuadrados  xd pues ya sabes tienes (a+b) (a-b)= $a^{2}-b^{2}$

1. (x-2)(x+2) tonces

(x-2)(x+2)= $x^{2}$-4

2. (a +3)(a -3) = $a^{2}$-9

4. (3x+2)(3x - 2) =9$x^{2}$-4

5. (3x + y)(3x - y) =9$x^{2}$-$y^{2}$

7. (7a -b)(7a +b)=49$a^{2}$- $b^{2}$

8. (5x+10y)(5x-10y) =25$x^{2}$-100$y^{2}$

10. (7$a^{2}$ +2$b^{2}$)(7$a^{2}$ -2$b^{2}$)=49$a^{4}$-4$b^{4}$

II. Resolver cada cuadrado de binomio busca la regla hija

$1. (x+4)^{2}=x^{2} +2 (4x)+8=x^{2} +8x+16\\ 2. (3x+2)^{2} =9x^{2} +2 (6x)+4=x^{2} +12x+4\\\\4. (p+5q)^{2} =p^{2} +2 (5pq)+25q^{2} =p^{2} +10pq+25q^{2} \\\\\\\5. (a+2b)^{2} =a^{2} +2 (2ab)+b^{2} =a^{2} +4ab+b^{2} \\\\7. (5x+3y)^{2} =25x^{2} +2 (15xy)+9y^{2} =25x^{2} +30xy+9y^{2} \\\\\\8. (a-3b)^{2} =a^{2} -2 (3ab)+9b^{2} =a^{2} -6ab+9b^{2} \\\\\\10. (6x-5y)^{2} =36x^{2} -2 (30xy)+25y^{2} =36x^{2} -60xy+25y^{2} \\\\\\11. (x^{2} -5)^{2} =x^{4} -2 (5x^{2} )+25=x^{4} -10x^{2} +25$

III producto

1.(x-2)(x+1)= $x^{2} +x-2x-2=x^{2} -x-2$

2.$(a+3)(a-2)=a^{2} -2a+3a-6=a^{2} +a-6$

4. $(4x+2)(x-5)=4x^{2} -20x+2x-10=4x^{2} -18x-10$

5. (5x-2)(5x-2)=$25x^{2} -2(10x)+4=25x^{2} -20x+4$

7. (4a-b)(3a+b)=$12a^{2} +4ab-3ab-b^{2} =12a^{2} +ab-b^{2}$

8.$(2x+5y)(5x+y)=10x^{2} +2xy+25xy+5y^{2} =10x^{2} +27xy+5y^{2}$

10.$(x-3)^{3} =x^{3} -3(x^{3}*3 )+3 (x*9)-27=x^{3} -9x^{3} +27x-27$ busca la regla hija

11.$(7a^{2} -b)(3a-2b)=21a^{3} -14a^{2} b-3ab+2b^{2}$