Question

2^5:[(√81-3^2)+ 4^2]

Answer 1

Respuesta:

$\frac{32\left(7-2\sqrt{2}\right)}{41}$

Explicación paso a paso:

$\frac{2^5}{\left(\sqrt{8}\cdot \:1-3^2\right)+4^2}\\\\=\frac{2^5}{\sqrt{8}\cdot \:1-3^2+4^2}\\\\=\frac{2^5}{7+\sqrt{8}}\\\\=\frac{2^5}{7+2\sqrt{2}}\\\\2^5=32\\\\=\frac{32}{7+2\sqrt{2}}\\\\=\frac{32\left(7-2\sqrt{2}\right)}{41}$