Question

Halla

Answer 1

Respuesta:

${139}^{0} + 2 \alpha - {1}^{0} = {180}^{0} \\ 2 \alpha = {180}^{0} - {139}^{0} + {1}^{0} \\ 2 \alpha = {42}^{0} \\ \alpha = \frac{ {42}^{0} }{2} \\ \alpha = {21}^{0}$

por lo que

$2 \alpha - {1}^{0} = 2( {21}^{0} ) - {1}^{0} = {42}^{0} - {1}^{0} = {41}^{0}$