Question

2tanx+1=cosx+2senx/cosx

Answer 1

2tanx+1=(cosx+2senx)/cosx

2(senx/cosx)+1=(cosx+2senx)/cosx

(2senx/cosx) +1=(cosx+2senx)/cosx

(2senx/cosx) +1(cosx/cosx)=(cosx+2senx)/cosx

(2senx/cosx) +(cosx/cosx)=(cosx+2senx)/cosx

(2senx+cosx)/cosx=(cosx+2senx)/cosx

(cosx+2senx)/cosx=(cosx+2senx)/cosx