Question

1-senx/cosx=cosx /1+senx

Answer 1

(1-senx)/cosx=cosx/(1+senx)

[(1-senx)/cosx](cosx/cosx)=cosx/(1+senx)

[(1-senx)(cosx)]/cos^2x=cosx/(1+senx)

[(1-senx)(cosx)]/(1-sen^2x)=cosx/(1+senx)

[(1-senx)(cosx)]/[(1-senx)(1+senx)]=cosx/(1+senx)

cosx/(1+senx)=cosx/(1+senx)