Question

Determine la masa molecular de los siguientes compuestos:
Fe2 O3 (oxido férrico)
Na OH (hidróxido de sodio)
H N O3 (ACIDO NITRICO)
C55 H72 Mg N4 O5 (CLOROFILA)
K Mn O4 (PERGAMANGATO DE POTASIO)
Cu Fe Po4 (FOSFATO CUPROSO FERROSO)
Na H Co3 (BICARBONATO DE SODIO)

porfa ayundenme es muy importante

Answer 1

Fe2 O3 (oxido férrico)
Fe: 2 x 55.84 = 111.68 g/mol
 O: 3 x 16 = 48 g/mol
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           Mm = 159.68 g/mol

Na OH (hidróxido de sodio)

Na: 1 x 23 = 23 g/mol
 O:  1 x 16 = 16 g/mol
  H: 1 x 1 = 1 g/mol
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           Mm = 40 g/mol

H N O3 (ACIDO NITRICO)

H: 1 x 1 = 1 g/mol
N: 1 x 14 = 14 g/mol
O: 3 x 16 = 48 g/mol
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       Mm = 63 g/mol

C55 H72 Mg N4 O5 (CLOROFILA)

C:  55 x 12 = 660 g/mol
H: 72 x 1 = 72 g/mol
Mg: 1 x 24 = 24 g/mol
 N: 4 x 14 = 56 g/mol
O:  5 x 16 = 80 g/mol
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           Mm = 892 g/mol
K Mn O4 (PERGAMANGATO DE POTASIO)

K: 1 x 39 = 39 g/mol
Mm: 1 x 54.9 = 54.9 g/mol
O: 4 x 16 = 64 g/mol
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           Mm = 157.9 g/mol

Cu Fe Po4 (FOSFATO CUPROSO FERROSO)

Cu: 1 x 63.54 = 63.54 g/mol
Fe: 1 x 55.84 = 55.84 g/mol
P:  1 x 30.97 = 30.97 g/mol
O:  4  x 16 = 64 g/mol
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             Mm = 214.35 g/mol

Na H Co3 (BICARBONATO DE SODIO)

Na: 1 x 23 = 23 g/mol
H: 1 x 1 = 1 g/mol
C: 1 x 12 = 12 g/mol
O: 3 x 16 = 48 g/mol
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           Mm = 84 g/mol