Question

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Answer 1

Mm ZnCl2 = 136.28 g/mol

              Zn = 65.38 g/mol

                          Zn + 2 HCl → ZnCl2 + H2

g ZnCl2 = 90 g Zn x 1 mol Zn x 1 mol ZnCl2 x 136.28 g Zn Cl2
                                 ````````````    ````````````````    ````````````````````
                                 65.38 g Zn   1 mol Zn        1 mol ZnCl2

g = 187.59 g de ZnCl2