Question

2 log5 3 - 1/3 log5 64 + log5 16???
forma condensada
Me urge, ayuden me

Answer 1

Respuesta: Log (base 5) [ 36 ]

Explicación paso a paso: Se sabe que :

Log (base B) N^(k)  = k Log(base B) N

Log M - Log N  = Log (M/N)

Log M + Log N  = Log (M . N)

Entonces:

2 log5 3 - 1/3 log5 64 + log5 16

= Log (3²) - Log (∛64) + Log 16

= Log [3² / (∛64)] + Log 16

= Log {[3² / (∛64)] . 16}

= Log [ 144 / (∛64) ]

= Log [ 144 / 4 ]

= Log [ 36 ]