Question

ayuden plisss................

Answer 1

Respuesta:

Fuerza: 470.4N

Presión en émbolo pequeño: 598.93 Pa

Presión émbolo grande: 598.93 Pa

Explicación:

Principio de Pascal:

$P1 = P2\\ \\ \frac{ F1}{A1} = \frac{ F2}{A2}$

Sustituyendo:

$\frac{(1200kg \times 9.8 \frac{m}{s {}^{2} }) }{\pi(2.5m) {}^{2} } = \frac{F2}{\pi(0.5m) {}^{2} } \\ \frac{11760N}{(3.1416)(6.25m {}^{2} )} = \frac{F2}{(3.1416)(0.25m {}^{2}) } \\ \frac{11760N}{19.635m {}^{2} } = \frac{F2}{0.7854m {}^{2} } \\ F2 = \frac{11760N \times 0.7854m {}^{2} }{19.635m {}^{2} } \\ F2 = \frac{9236.304Nm {}^{2} }{19.635m {}^{2} } \\ F2 = 470.4N$

$P = \frac{ F}{A} \\ P = \frac{11760N}{19.635m {}^{2} } \\ P = 598.93Pa$

$P = \frac{470.4N}{0.7854m {}^{2} } \\P = 598.93Pa$