Question

A = 2[4/3 - (1/2 + 2/5) -1/3 ]

Answer 1

Respuesta:

a= 1/5

Explicación paso a paso:

a= 2(4/3-(1/2+2/5)-1/3)

a = 2 (4/3- 1/2 - 2/5 - 1/3)

a= 2 enteros 1/10

a= 2/10

a= 1/5

Answer 2

RESPUESTA:

$A=2\left[\frac{4}{3}-\left(\frac{1}{2}+\frac{2}{5}\right)-\frac{1}{3}\right]$

$\frac{4}{3}-\left(\frac{1}{2}+\frac{2}{5}\right)-\frac{1}{3}$

$=\frac{4}{3}-\frac{1}{3}-\left(\frac{1}{2}+\frac{2}{5}\right)$

$\mathrm{Aplicar\:la\:regla}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{3}{3}$

$\mathrm{Aplicar\:la\:regla}\:\frac{a}{a}=1$

$=1$

$Entonces$

$=1-\left(\frac{1}{2}+\frac{2}{5}\right)$

$A=2\left(-\left(\frac{1}{2}+\frac{2}{5}\right)+1\right)$

$A=2\left(-\frac{9}{10}+1\right)$

$A=2\cdot \frac{1}{10}$

$\mathrm{Multiplicar\:fracciones}:\quad \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}$

$A=\frac{1\cdot \:2}{10}$

$A=\frac{2}{10}$

$\mathrm{Eliminar\:los\:terminos\:comunes:}\:2$

$A=\frac{1}{5}$

$RPTA=\frac{1}{5}$

【ツ】亗 CORONA 亗