Question

resuelve las sumas utilizando el método de productos cruzados

Answer 1

Respuesta:

$\frac{2}{3} + \frac{1}{6} = \frac{2(2) + 1(6)}{6} = \frac{4 + 6}{6} = \frac{10}{6} = \frac{5}{3} \\ \\ \frac{4}{5} + \frac{1}{3} = \frac{3(4) +5(1) }{15} = \frac{12 + 5}{15} = \frac{17}{15} = 1 \times \frac{2}{ 15} \\ \\ \frac{3}{5} + \frac{1}{4} = \frac{4(3) + 5(1)}{20} = \frac{12 + 5}{20} = \frac{17}{20} \\ \\ \frac{3}{10} + \frac{1}{2} = \frac{2(3) + 5(1)}{20} = \frac{6 + 5}{20} = \frac{11}{20} \\ \\ \frac{7}{14} + \frac{4}{7} = \frac{1(7) + 2(4)}{14} = \frac{7 + 8}{14} = \frac{15}{14} = 1 \times \frac{1}{14} \\ \\ \frac{3}{4} > \frac{1}{2} \\ \\ \frac{5}{6} > \frac{4}{7} \\ \\ \frac{3}{5} < \frac{5}{7} \\ \\ \frac{2}{3} < \frac{6}{15} \\ \\ \frac{8}{11} < \frac{7}{8} \\ \\ \frac{3}{8} < \frac{8}{3}$