Question

encontrar "Y" 3y+d=dy+2(d+y)-5(d+4)

Answer 1

3y + d = dy + 2(d + y) - 5(d + 4)
3y + d = dy + 2d + 2y - 5d + 20
3y - 2y + d - 2d + 5d - dy - 20 = 0
y + 4d - dy - 20 = 0
y - dy + 4d = 20
y (1 - d) + 4d = 20
y = (20 - 4d) / (1 - d)
y = 4 (5 - d) / (1 - d)
Así lo podrías resolver