Question

$(b - \frac{1}{3} {)}^{3}$
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Answer 1

Respuesta:

$b ^{3} - 3b ^{2} \times \frac{1}{3} + 3b \times ( \frac{1}{3})^{2} - ( \frac{1}{3})^{3} \\ \\ b ^{3} - b^{2} + 3b \times \frac{1}{9} - \frac{1}{27} \\ \\ b ^{3} - b^{2} + \frac{1}{3}b - \frac{1}{27}$

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