Question

(8x3-10x2y+2xy)÷(4x2-3xy)​

Answer 1

Respuesta:

$\frac{2\left(4x^2-5xy+y\right)}{4x-3y}$

Explicación paso a paso:

$\frac{8x^3-10x^2y+2xy}{4x^2-3xy}$

$\frac{2x\left(4x^2-5xy+y\right)}{4x^2-3xy}$

$\frac{2x\left(4x^2-5xy+y\right)}{x\left(4x-3y\right)}$

$\frac{2\left(4x^2-5xy+y\right)}{4x-3y}$