Question

3x (x + 7) + 2 (x +3) = x + 39​

Answer 1

Respuesta:

$x_{1} =\frac{-11+2\sqrt{55} }{3} , x_{2}=-\frac{11+2\sqrt{55} }{3}$

Explicación:

$3x (x + 7) + 2 (x +3) = x + 39$

$3x(x)+3x(7)+2(x)+2(3)=x+39$

$3x^{2} +21x+2x+6=x+39$

$3x^{2} +23x+6=x+39$

$3x^{2} +23x-x=39-6$

$3x^{2} +22x=33$

$3x^{2} +22x-33=0$

$x_{1,2} =\frac{-22\frac{+}{-} 4\sqrt{55} }{2*3}$

$x_{1} =\frac{-22+4\sqrt{55} }{2*3} , x_{2}=\frac{-22-4\sqrt{55} }{2*3}$

$x_{1} =\frac{-11+2\sqrt{55} }{3} , x_{2}=-\frac{11+2\sqrt{55} }{3}$