Question

AYUDA PLEASE
DOY 20 PUNTOS Y CORONA
SI NA SABEN NO RESPONDAN

Answer 1

Respuesta:

En el Paso a Paso

Explicación paso a paso:

a.- $(-2.34)^{0} = 1$ (Todo numero elevado a la "0"da 1)

b.- $(\frac{5}{7} )^{0} = 1$

c.- $(-\pi )^{0} = 1$

d.- $5^{3}. 5^{4} = 5^{3+4} = 5^{7}$

e.- $\sqrt[3]{7^{2} } . \sqrt[3]{7^{4} } = 7^{\frac{2}{3} } . 7^{\frac{4}{3} }= 7^{\frac{2+4}{3} } = 7^{\frac{6}{3} } = 7^{2} = 49$

f.- $(\frac{-3}{5})^{3} . (\frac{-3}{5} )^{2} = (\frac{-3}{5})^{3+2} = (\frac{-3}{5})^{5} = \frac{-243}{3125}$

g.- $(0,123)^{3} . (7)^{3} = 0,63$

h.- $(\frac{2}{5})^{4} . (\frac{3}{5} )^{4} = \frac{16}{625} . \frac{81}{625} =\frac{1296}{390625}$

i.- $(-2)^{2} . (-2)^{2} = (-2)^{2+2} = (-2)^{4} = 16$

j.- $(\frac{3}{5} )^{4} / (\frac{5}{3} )^{3} = ( \frac{81}{625})/ ( \frac{125}{9})=\frac{81 . 9}{625 . 125} = \frac{729}{78125}$

k.- $\frac{\sqrt{2}^{5} }{\sqrt{2}^{3} } = \frac{2^{\frac{5}{2} } }{2^{\frac{3}{2} } } = 2^{5/2 -3/2} = 2^{2/2} = 2^{1} =2$

l.- $\frac{(-5)^{7} }{(-5)^{6} } = (-5) ^{7-6} = (-5)^{1} =-5$

m.- $\sqrt[4]{6^{1} } = (6)^{\frac{1}{4} } = (6)^{0,25} = 1,56$

n.- $(\frac{5}{3} )^{2} = \frac{5.5}{3.3} =\frac{25}{9}$