Question

resolver la ecuación : 2senx•cosx-cosx=0​

Answer 1

RESPUESTA:

$2\sin \left(x\right)\times \cos \left(x\right)-\cos \left(x\right)=0$

$\cos \left(x\right)\left(2\sin \left(x\right)-1\right)=0$

$\mathrm{Resolver\:cada\:parte\:por\:separado}$

$\cos \left(x\right)=0\quad \mathrm{or}\quad \:2\sin \left(x\right)-1=0$

$x=\frac{\pi }{2}+2\pi n,\:x=\frac{3\pi }{2}+2\pi n,\:x=\frac{\pi }{6}+2\pi n,\:x=\frac{5\pi }{6}+2\pi n$

$RPTA:x=\frac{\pi }{2}+2\pi n,\:x=\frac{3\pi }{2}+2\pi n,\:x=\frac{\pi }{6}+2\pi n,\:x=\frac{5\pi }{6}+2\pi n$

【ツ】亗 CORONA 亗