Hola, necesito ayuda con lo siguiente, (se utilizando la fórmula de binomio al cuadrado y conjugado)
cuadrado:
(5a+2)²=
(4a²+2b)²=
(11x+7y³)²=
(4c⁴+5cd)²
conjugado:
(a+2)(a-2)=
(7a²-3b)(7a²+3b)=
(6ab+2cd)(6ab-2cd)=
(8a³b⁴+1)(8a³b⁴-1)=
(12x²-10)(12x²+10)=
(reporto respuestas que no vengan al tema o a personas que solo quieran robar puntos)
Respuestas
Explicación paso a paso:
Formula de binomio al cuadrado:
(a ± b)² = a² ± 2ab + b²
Resolvamos:
(5a+2)² = (5a)² + 2(5a)(2) + (2)²
(5a+2)² = 25a²+20a+4
(4a²+2b)² = (4a²)² + 2(4a²)(2b) + (2b)²
(4a²+2b)² = 16a⁴+16a²b+4b²
(11x+7y³)² = (11x)² + 2(11x)(7y³) + (7y³)²
(11x+7y³)² = 121x²+154xy³+49y⁶
(4c⁴+5cd)² = (4c⁴)² + 2(4c⁴)(5cd) + (5cd)²
(4c⁴+5cd)² = 16c⁸+40c⁴cd+25c²d²
Formula de binomios conjugados:
(a + b)(a - b) = a² - b²
Resolvamos:
(a+2)(a-2) = (a)² - (2)²
(a+2)(a-2) = a²-4
(7a²-3b)(7a²+3b) = (7a²)² - (3b)²
(7a²-3b)(7a²+3b) = 49a⁴-9b²
(6ab+2cd)(6ab-2cd) = (6ab)² - (2cd)²
(6ab+2cd)(6ab-2cd) = 36a²b²-4c²d²
(8a³b⁴+1)(8a³b⁴-1) = (8a³b⁴)² - (1)²
(8a³b⁴+1)(8a³b⁴-1) = 64a⁶b⁸-1
(12x²-10)(12x²+10) = (12x²)² - (10)²
(12x²-10)(12x²+10) = 144x⁴-100