Question

2. Astronaut Spaceman uses a small mass attached to a 3.25 m length of string to figure out the acceleration due to gravity on Mars. He timed the pendulum's period to be 1.2 seconds. What were his results? The formula needed is g = 4T2L/ T2 ​

Answer 1

Respuesta:

${0 { {x { { {2225426}^{2} \times \frac{?}{?} }^{2} }^{?} }^{2} }^{?} \times \frac{?}{?} }^{2}$