Question

Determina la fórmula empírica y la formula molecular de carbono con el cloro C 7.79 CL 92.21 masa molecular 154 ayuda plz ?

Answer 1

Mm C = 12 g/mol
       Cl = 35.4 g/mol

calcular moles de cada elemento:

C: 7.79 g/ 12 g/mol = 0.649 mol
Cl: 92.21 g/ 35.4 g/mol = 2.604 mol

2. dividir cada elemento entre el menor de los resultados:

C:  0.649 mol / 0.649 mol = 1
Cl: 2.604 mol / 0.649 mol = 4

3. FORMULA EMPIRICA: CCL4

4.Calcular Mm de la FE:
C:  1 x 12  = 12 g /mol
Cl: 4 x 35.4 = 141.6 g/mol
``````````````````````````````````
             Mm = 153.6 g/mol

n = 154 g/mol / 153.6 g/mol
n = 1

5. FORMULA MOLECULAR:

FM = (CCl4)1 = CCl4 (tetracloruro de carbono