Question

N=(x+1)(x-1)(x^2+1)+1

Answer 1

$N=\left(x+1\right)\left(x-1\right)\left(x^2+1\right)+1$
$\mathrm{Poner\:los\:parentesis\:utilizando}:\quad \left(a+b\right)\left(a-b\right)=a^2-b^2$
$\left(x+1\right)\left(x-1\right)$
$=x^2-1$
$N=\left(x^2-1\right)\left(x^2+1\right)+1$
$\mathrm{Poner\:los\:parentesis\:utilizando}:\quad \left(a-b\right)\left(a+b\right)=a^2-b^2$
$N=\left(x^2\right)^2-1^2+1$
$N=x^4-1+1$
$N= x^{4}$