Question

ayuda no logro en tender le

9449e6427adc582bd2bd735326590bc6.docx

Answer 1

1)$\frac{1}{2} x+ \frac{1}{3} x=5$

$\frac{3(1)}{3(2)} x + \frac{2(1)}{2(3)} x=5$

$\frac{3}{6} x + \frac{2}{6} x= 5$

$\frac{5}{6} x=5$

5x=5(6)

5x=30

x=$\frac{30}{5}$

x=6

2) $\frac{1}{3} x - \frac{1}{2}+ \frac{5}{6} x= 3$

$\frac{1}{3} x+ \frac{5}{6} x= 3 + \frac{1}{2}$

$\frac{2(1)}{2(3)} x+ \frac{5}{6}x= \frac{2(3)}{2}+ \frac{1}{2}$

$\frac{2}{6}x+ \frac{5}{6}x= \frac{6}{2}+ \frac{1}{2}$

$\frac{7}{6}x= \frac{7}{2}$

$7x= (\frac{7}{2})6$

$7x= 21$

$x= \frac{21}{7}$

x=3

3) $\frac{3}{4}x+ 2= \frac{5}{6} x+1$

$2-1= \frac{5}{6}x- \frac{3}{4}x$

$1= \frac{20-18}{24}x$

$1= \frac{2}{24}x$

$1=\frac{1}{12}x$

1(12)=x

12=x

4) $\frac{x}{2}+ 6- \frac{x}{4}= \frac{2}{5}x+3$

$6-3= \frac{2x}{5}+ \frac{x}{4}- \frac{x}{2}$

$3= \frac{4(2x)+5(x)-10(x)}{20}$

$3= \frac{8x+5x-10x}{20}$

$3= \frac{3x}{20}$

3(20) = 3x

60=3x

$\frac{60}{3}=x$

20=x

5) $\frac{5x}{6}- \frac{x}{18}- \frac{3x}{4}= \frac{7}{12}- \frac{2X}{9}+ \frac{2}{3}$

$\frac{5x}{6}- \frac{x}{18}- \frac{3x}{4}+ \frac{2x}{9}= \frac{7}{12}+ \frac{2}{3}$

$\frac{12(5x)-4(x)-18(3x)+8(2x)}{72}= \frac{7+4(2)}{12}$

$\frac{60x-4x-54x+16x}{72}= \frac{7+8}{12}$

$\frac{18x}{72}= \frac{15}{12}$

$\frac{x}{4}= \frac{5}{4}$

$x= \frac{4(5)}{4}$

$x= \frac{20}{4}$

$x=5$